Area 1/2=Absinc

sector 1/2=ab intrudeC * (Obtuse Acute) Area formula Where b = petty(a) length and h = apex. When you have two sides and their included angle, the law of sinfulness can be used in finding the area of the diverging triangle. For the base, we use one of the sides lets say we have base c For the height draw an perpendicular line from C to the base line c. * For the bang-up case an extended base line can be make to show this altitude, as h will touch the base outside the triangle.In the obtuse triangle do we now have two set triangles and find h by taking the sine Sin = opp/hyp two is now sat equal to h and can be substituted in for the height in the originally triangle formula. Eq. b sinA = h pes c Area = (base)(height) Area = (base)(b SinA) Area= (c)(b SinA) As it has no define in which order the base and the opposite value comes, they will be arranged alphabetically. * Area = bc SinA * When the base = c and the height = (a sin B) When the base = c and the height = ( b sin A) If eq. were used as a base, the height would equal (a sin C) + Example + label ABC A= 65 degrees b= 5 a= 7 c = 8 Area= . 5 (b)(h) To find the height take the Sin (opposite/hypp) thusly well have h/b b= 5 Sin (A) = (h/b) = = bSin(A) = h Sin(65) = (h/5) == 5Sin(65) = h In order not to handle too galore(postnominal) numbers we can substitute this into the area equation * * Area = ? (b)(h) * Area = ? (c)(bSinA) Usually arranged alphabetically (bcSinA) * * Then substitute the values into this bare-assed equation * * Area = 1/2 (8)(5Sin(65)) * Area = 16. 53657358980207 * ? 16. 54 cm2 * * *